Cociente de potencia: Variables en el exponente de la potencia

Resuelva el ejercicio

$\frac{a^{3b}}{a^{2b}}\times a^b=$

$a^{2b}$

Resuelve el siguiente ejercicio

$\frac{a^{xy}}{a^{3xy}}-a^{2xy}$

$a^{-2xy}-a^{2xy}$

$\frac{11^{2a}}{11^5}=$

$11^{2a-5}$

$\frac{2^a}{2^2}=$

$2^{a-2}$

$\frac{4^5}{4^x}=$

$4^{5-x}$

$\frac{7^{5b}}{7^{2b}}=$

$7^{5b-2b}$

$\frac{9^x}{9^y}=$

$9^{x-y}$

$$$\frac{3^{2a}}{3^a}=$

$3^a$

$\frac{6^{4x}}{6^{x+1}}=$

$6^{3x-1}$

$\frac{11^{5a}}{11^{a+4}}=$

$11^{4a-4}$

$\frac{16^{x+4}}{16^3}=$

$16^{x+1}$

$\frac{20^{x+y}}{20^{a+y}}=$

$20^{x-a}$

$\frac{\left(4\times7\right)^{2x}}{\left(4\times7\right)^4}=$

$\left(4\times7\right)^{2x-4}$

$\frac{\left(12\times2\right)^5}{\left(2\times12\right)^{3y}}=$

$\left(12\times2\right)^{5-3y}$

$\frac{\left(3\times14\right)^{a+1}}{\left(3\times14\right)^2}=$

$\left(3\times14\right)^{a+1-2}$

$$$\frac{\left(9\times7\right)^{2x}}{\left(7\times9\right)^{2y}}=$

$\left(9\times7\right)^{2x-2y}$

$\frac{\left(15\times6\right)^{ax}}{\left(15\times6\right)^{y+1}}=$

$\left(15\times6\right)^{ax-y-1}$

$\frac{\left(3\times7\right)^{2x+5}}{\left(3\times7\right)^{x+3}}=$

$\left(3\times7\right)^{x+2}$

$\frac{\left(2\times9\right)^{x+7}}{\left(9\times2\right)^{y+4}}=$

$\left(9\times2\right)^{x-y+3}$

$\frac{\left(5\times8\right)^{3+5y}}{\left(8\times5\right)^{3y+1}}=$

$\left(5\times8\right)^{2y+2}$